Solve: xx+1+1x−1=2x2−3x2−1\dfrac{x}{x+1} + \dfrac{1}{x-1} = \dfrac{2x^2 - 3}{x^2-1}x+1x+x−11=x2−12x2−3.
x=2x = 2x=2
x=−2x = -2x=−2
x=1x = 1x=1
No solution