Solve cos(2x)=sin(x)\cos(2x) = \sin(x)cos(2x)=sin(x) for x∈[0,π]x \in [0, \pi]x∈[0,π].
π6,5π6\frac{\pi}{6}, \frac{5\pi}{6}6π,65π
π2\frac{\pi}{2}2π
π6,5π6,3π2\frac{\pi}{6}, \frac{5\pi}{6}, \frac{3\pi}{2}6π,65π,23π
π6\frac{\pi}{6}6π