Solve cos(2x)=sin(x)\cos(2x) = \sin(x)cos(2x)=sin(x) for x∈[0,2π]x \in [0, 2\pi]x∈[0,2π].
π/6,5π/6,3π/2\pi/6, 5\pi/6, 3\pi/2π/6,5π/6,3π/2
π/3,2π/3\pi/3, 2\pi/3π/3,2π/3
π/6,5π/6,π\pi/6, 5\pi/6, \piπ/6,5π/6,π
π/4,3π/4\pi/4, 3\pi/4π/4,3π/4