Ononot — Solve an = 4a{n-1} - 4a{n-2} with a0 = 1, a1 = 4. What is a3

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Recursionhard

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Solve $a_n = 4a_{n-1} - 4a_{n-2}$ with $a_0 = 1, a_1 = 4$ . What is $a_3$ ?