Ononot — Solve an = 4a{n-1} - 3a{n-2} with a0 = 2 and a1 = 5. Find a3

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Recurrence Relationshard

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Solve $a_n = 4a_{n-1} - 3a_{n-2}$ with $a_0 = 2$ and $a_1 = 5$ . Find $a_3$ .