Solve an=2an−1−an−2a_n = 2a_{n-1} - a_{n-2}an=2an−1−an−2 with a0=1,a1=3a_0 = 1, a_1 = 3a0=1,a1=3. What is ana_nan?
an=2n+1a_n = 2n + 1an=2n+1
an=n2+1a_n = n^2 + 1an=n2+1
an=3na_n = 3^nan=3n
an=n+2a_n = n + 2an=n+2