Solve: (3x−2)2>16(3x-2)^2 > 16(3x−2)2>16
x>2x > 2x>2
x<−23x < -\frac{2}{3}x<−32
x<−23x < -\frac{2}{3}x<−32 or x>2x > 2x>2
−23≤x≤2-\frac{2}{3} \leq x \leq 2−32≤x≤2