Solve: 3≤∣x∣<53 \leq |x| < 53≤∣x∣<5
[−5,−3]∪[3,5)[-5, -3] \cup [3, 5)[−5,−3]∪[3,5)
(−5,−3)∪(3,5)(-5, -3) \cup (3, 5)(−5,−3)∪(3,5)
[−5,5)[-5, 5)[−5,5)
{−5,−3,3,5}\{-5, -3, 3, 5\}{−5,−3,3,5} (finitely many points)