Simplify the expression xn+1nxnn+1\frac{\sqrt[n]{x^{n+1}}}{\sqrt[n+1]{x^n}}n+1xnnxn+1 for x>0x > 0x>0.
x1n(n+1)x^{\frac{1}{n(n+1)}}xn(n+1)1
x2n+1n(n+1)x^{\frac{2n+1}{n(n+1)}}xn(n+1)2n+1
xxx
xn2x^{n^2}xn2