Simplify the boolean expression: (P∧Q)∨(P∧¬Q)∨(egP∧Q)(P \land Q) \lor (P \land \neg Q) \lor ( eg P \land Q)(P∧Q)∨(P∧¬Q)∨(egP∧Q)
P∧QP \land QP∧Q
P∨QP \lor QP∨Q
True
egP∨Q eg P \lor QegP∨Q