Simplify: x+4x2−16\dfrac{x+4}{x^2 - 16}x2−16x+4 for x≠4,−4x \neq 4, -4x=4,−4.
1x−4\dfrac{1}{x-4}x−41
1x+4\dfrac{1}{x+4}x+41
x−4x - 4x−4
x+4x−4\dfrac{x+4}{x-4}x−4x+4