Simplify: x3−xx2+x\dfrac{x^3 - x}{x^2 + x}x2+xx3−x (assume x≠0,−1x \neq 0, -1x=0,−1).
x−1x - 1x−1
x+1x + 1x+1
x2−1x^2 - 1x2−1
x2−1x\dfrac{x^2 - 1}{x}xx2−1