Simplify: x2+2x−8x2−2x\dfrac{x^2 + 2x - 8}{x^2 - 2x}x2−2xx2+2x−8 (assume x≠0,2x \neq 0, 2x=0,2).
x+4x\dfrac{x + 4}{x}xx+4
x−4x\dfrac{x - 4}{x}xx−4
x+4x−2\dfrac{x + 4}{x - 2}x−2x+4
x−2x\dfrac{x - 2}{x}xx−2