Simplify: (x+1)2x2−1\dfrac{(x+1)^2}{x^2 - 1}x2−1(x+1)2 (assume x≠±1x \neq \pm 1x=±1).
x+1x−1\dfrac{x+1}{x-1}x−1x+1
x−1x+1\dfrac{x-1}{x+1}x+1x−1
x+1x + 1x+1
(x+1)2(x−1)\dfrac{(x+1)^2}{(x-1)}(x−1)(x+1)2