Show that n3−nn^3-nn3−n is divisible by 6 for all integers nnn. What is the factored form?
n(n−1)(n+1)n(n-1)(n+1)n(n−1)(n+1)
n(n2−1)n(n^2-1)n(n2−1)
(n−1)(n2+n)(n-1)(n^2+n)(n−1)(n2+n)
6n6n6n