Prove that for any valid bases a,b>0a, b > 0a,b>0 (both ≠1\neq 1=1) and positive xxx: loga(x)=logb(x)logb(a)\log_a(x) = \frac{\log_b(x)}{\log_b(a)}loga(x)=logb(a)logb(x)
This is the Change of Base Formula
This follows from the definition of logarithm
This is always true by properties of exponents
All of the above are true