Multiply: 3x+1⋅x2−16\dfrac{3}{x+1} \cdot \dfrac{x^2 - 1}{6}x+13⋅6x2−1.
x−12\dfrac{x-1}{2}2x−1
x+12\dfrac{x+1}{2}2x+1
x−16\dfrac{x-1}{6}6x−1
3(x−1)x+1\dfrac{3(x-1)}{x+1}x+13(x−1)