Multiply: \acx−35\ot\ac10x2−9\ac{x-3}{5} \ot \ac{10}{x^2 - 9}\acx−35\ot\ac10x2−9.
\ac2x+3\ac{2}{x+3}\ac2x+3
\ac2x−3\ac{2}{x-3}\ac2x−3
2(x+3)2(x+3)2(x+3)
1