Let xn=xn−11+2xn−1x_n = \frac{x_{n-1}}{1 + 2x_{n-1}}xn=1+2xn−1xn−1 for n≥1n \geq 1n≥1 with x0=1x_0 = 1x0=1. What is the closed-form expression for xnx_nxn?
xn=12n+1x_n = \frac{1}{2n+1}xn=2n+11
xn=12nx_n = \frac{1}{2^n}xn=2n1
xn=1n2+1x_n = \frac{1}{n^2 + 1}xn=n2+11
xn=12n−1x_n = \frac{1}{2n-1}xn=2n−11