Let X∼Poisson(λ)X \sim \text{Poisson}(\lambda)X∼Poisson(λ) with E[X]=5E[X] = 5E[X]=5. What is P(X=0)P(X=0)P(X=0)?
e−5e^{-5}e−5
5e−55e^{-5}5e−5
1e5\frac{1}{e^5}e51
e5e^{5}e5