Let XXX have PDF f(x)=k(1−∣x∣)f(x) = k(1-|x|)f(x)=k(1−∣x∣) for ∣x∣≤1|x| \le 1∣x∣≤1. Find kkk.
k=1k = 1k=1
k=1/2k = 1/2k=1/2
k=2k = 2k=2
k=1/4k = 1/4k=1/4