Let XXX have PDF f(x)=12πf(x) = \frac{1}{2\pi}f(x)=2π1 for 0≤x≤2π0 \le x \le 2\pi0≤x≤2π. Find E[X]E[X]E[X].
π\piπ
π/2\pi/2π/2
2π2\pi2π
π2\pi^2π2