Let XXX be a random variable with MGF MX(t)=e5t1−4tM_X(t) = \frac{e^{5t}}{1 - 4t}MX(t)=1−4te5t for t<0.25t < 0.25t<0.25. Calculate E[X2]E[X^2]E[X2].
41
45
57
65