Ononot — Let u = \begin{pmatrix} 1 \\ 2 \end{pmatrix} and v = \begin{

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Matriceshard

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Let $u = \begin{pmatrix} 1 \\ 2 \end{pmatrix}$ and $v = \begin{pmatrix} 3 \\ 1 \end{pmatrix}$ . By the matrix determinant lemma, $\det(I + uv^T) = 1 + v^T u$ for conformable dimensions. What is $\det(I + uv^T)$ where $I$ is the $2 \times 2$ identity?