Let P(n)=n4+n2+1P(n) = n^4 + n^2 + 1P(n)=n4+n2+1. What is gcd(P(n),P(n+1))\text{gcd}(P(n), P(n+1))gcd(P(n),P(n+1))?
111
333
n2+n+1n^2+n+1n2+n+1
n2−n+1n^2-n+1n2−n+1