Let nnn be an integer. For which of the following is n2+n+1n^2 + n + 1n2+n+1 divisible by 131313?
n≡3(mod13)n \equiv 3 \pmod{13}n≡3(mod13)
n≡4(mod13)n \equiv 4 \pmod{13}n≡4(mod13)
n≡9(mod13)n \equiv 9 \pmod{13}n≡9(mod13)
n≡10(mod13)n \equiv 10 \pmod{13}n≡10(mod13)