Let g(x)=∫0x2sin(xy) dyg(x) = \int_0^{x^2} \sin(x y) \, dyg(x)=∫0x2sin(xy)dy. Find the derivative g′(x)g'(x)g′(x) using the Leibniz Integral Rule.
3xsin(x3)+cos(x3)−1x23x \sin(x^3) + \frac{\cos(x^3) - 1}{x^2}3xsin(x3)+x2cos(x3)−1
2xsin(x3)+cos(x3)−1x22x \sin(x^3) + \frac{\cos(x^3) - 1}{x^2}2xsin(x3)+x2cos(x3)−1
3xsin(x3)+cos(x3)x23x \sin(x^3) + \frac{\cos(x^3)}{x^2}3xsin(x3)+x2cos(x3)
2xsin(x3)−1x22x \sin(x^3) - \frac{1}{x^2}2xsin(x3)−x21