Let f(x,y)=x3−3xy2+y3f(x, y) = x^3 - 3xy^2 + y^3f(x,y)=x3−3xy2+y3. Find the total differential dfdfdf at the point (1,−1)(1, -1)(1,−1) given dx=0.01dx = 0.01dx=0.01 and dy=−0.02dy = -0.02dy=−0.02.
df=−0.09df = -0.09df=−0.09
df=0.09df = 0.09df=0.09
df=−0.03df = -0.03df=−0.03
df=0.03df = 0.03df=0.03