Let f(x)=∫xx3ln(t)tdtf(x) = \int_{x}^{x^3} \frac{\ln(t)}{t} dtf(x)=∫xx3tln(t)dt for x>0x > 0x>0. Find f′(e)f'(e)f′(e).
9−1/e9 - 1/e9−1/e
9−19 - 19−1
888
1−1/e1 - 1/e1−1/e