Let f(x)=∫xx2arctan(t)dtf(x) = \int_{x}^{x^2} \arctan(t) dtf(x)=∫xx2arctan(t)dt. What is f′′(1)f''(1)f′′(1)?
2\arctan(1) - 1/2
2 + 1/2
4\arctan(1) - 1
2\arctan(1) + 1/2