Let f(x)=∫x3xcos(t2)dtf(x) = \int_{x^3}^{\sqrt{x}} \cos(t^2) dtf(x)=∫x3xcos(t2)dt. Find f′(1)f'(1)f′(1).
12cos(1)−3cos(1)\frac{1}{2}\cos(1) - 3\cos(1)21cos(1)−3cos(1)
12cos(1)+3cos(1)\frac{1}{2}\cos(1) + 3\cos(1)21cos(1)+3cos(1)
cos(1)−3cos(1)\cos(1) - 3\cos(1)cos(1)−3cos(1)
−52cos(1)-\frac{5}{2}\cos(1)−25cos(1)