Let f(x)=∫0x2sin(t2)t2dtf(x) = \int_{0}^{x^2} \frac{\sin(t^2)}{t^2} dtf(x)=∫0x2t2sin(t2)dt. Determine the limit L=limx→0f(x)x6L = \lim_{x \to 0} \frac{f(x)}{x^6}L=limx→0x6f(x).
L=1L = 1L=1
L=1/3L = 1/3L=1/3
L=1/6L = 1/6L=1/6
L=0L = 0L=0