Let f(x)=ln(1+4x2)cos(3x)−1f(x) = \frac{\ln(1+4x^2)}{\cos(3x)-1}f(x)=cos(3x)−1ln(1+4x2). Evaluate limx→0f(x)\lim_{x \to 0} f(x)limx→0f(x).
−89-\frac{8}{9}−98
−49-\frac{4}{9}−94
43\frac{4}{3}34
−1-1−1