Let f(x)=1x−3f(x) = \frac{1}{x-3}f(x)=x−31. Find f−1(x)f^{-1}(x)f−1(x) and its domain.
f−1(x)=1x+3f^{-1}(x) = \frac{1}{x} + 3f−1(x)=x1+3, x≠0x \neq 0x=0
f−1(x)=1x−3f^{-1}(x) = \frac{1}{x} - 3f−1(x)=x1−3, x≠0x \neq 0x=0
f−1(x)=1x+3f^{-1}(x) = \frac{1}{x+3}f−1(x)=x+31, x≠−3x \neq -3x=−3
f−1(x)=x−3f^{-1}(x) = x-3f−1(x)=x−3, all real xxx