Let f(x)={xpsin(1/xq)x≠00x=0f(x) = \begin{cases} x^p \sin(1/x^q) & x \neq 0 \\ 0 & x = 0 \end{cases}f(x)={xpsin(1/xq)0x=0x=0. For what relationship between ppp and qqq is fff differentiable at x=0x=0x=0?
p>qp > qp>q
p>0p > 0p>0
p>q+1p > q+1p>q+1
p>1p > 1p>1