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GCD & LCMmedium
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Let FnF_nFn​ denote the nnn-th Fibonacci number. For consecutive Fibonacci numbers, gcd⁡(Fn,Fn+1)=?\gcd(F_n, F_{n+1}) = ?gcd(Fn​,Fn+1​)=? for all n≥1n \geq 1n≥1.