Let f:R∖{0}→Rf: \mathbb{R} \setminus \{0\} \to \mathbb{R}f:R∖{0}→R satisfy f(x)+2f(1/x)=3xf(x) + 2f(1/x) = 3xf(x)+2f(1/x)=3x. Find f(x)f(x)f(x).
f(x)=2/x−xf(x) = 2/x - xf(x)=2/x−x
f(x)=2x−1/xf(x) = 2x - 1/xf(x)=2x−1/x
f(x)=3x−2/xf(x) = 3x - 2/xf(x)=3x−2/x
f(x)=1/x−2xf(x) = 1/x - 2xf(x)=1/x−2x