Let An=[1+(−1)nn,3−12n]A_n = \left[1 + \frac{(-1)^n}{n}, 3 - \frac{1}{2^n}\right]An=[1+n(−1)n,3−2n1] for n∈Nn \in \mathbb{N}n∈N. Determine the set S=⋂n=1∞AnS = \bigcap_{n=1}^{\infty} A_nS=⋂n=1∞An.
[1,3][1, 3][1,3]
[1.5,2.5][1.5, 2.5][1.5,2.5]
(1,3)(1, 3)(1,3)
[1,2.5][1, 2.5][1,2.5]