Let ana_nan be a sequence such that limn→∞an+1an=L\lim_{n \to \infty} \frac{a_{n+1}}{a_n} = Llimn→∞anan+1=L. For the recurrence an=3an−1+4an−2a_n = 3a_{n-1} + 4a_{n-2}an=3an−1+4an−2, what is LLL?
333
444
2+22 + \sqrt{2}2+2