Let A=(1,2)A=(1, 2)A=(1,2) and B=(4,6)B=(4, 6)B=(4,6). Find the equation of the locus of points PPP such that ∠APB=90∘\angle APB = 90^\circ∠APB=90∘.
x2+y2−5x−8y+16=0x^2 + y^2 - 5x - 8y + 16 = 0x2+y2−5x−8y+16=0
x2+y2−4x−6y+10=0x^2 + y^2 - 4x - 6y + 10 = 0x2+y2−4x−6y+10=0
x2+y2+5x+8y−16=0x^2 + y^2 + 5x + 8y - 16 = 0x2+y2+5x+8y−16=0
2x2+2y2−5x−8y=02x^2 + 2y^2 - 5x - 8y = 02x2+2y2−5x−8y=0