Let A={x∈R:x2−4x+3<0}A = \{x \in \mathbb{R} : x^2 - 4x + 3 < 0\}A={x∈R:x2−4x+3<0}. Express AAA in interval notation.
(1,3)(1, 3)(1,3)
\(-\infty, 1) \cup (3, \infty)
[1,3][1, 3][1,3]
∅\emptyset∅