Let A=(2102)A = \begin{pmatrix} 2 & 1 \\ 0 & 2 \end{pmatrix}A=(2012). Calculate AnA^nAn.
(2nn2n−102n)\begin{pmatrix} 2^n & n 2^{n-1} \\ 0 & 2^n \end{pmatrix}(2n0n2n−12n)
(2n2n02n)\begin{pmatrix} 2^n & 2^n \\ 0 & 2^n \end{pmatrix}(2n02n2n)
(4nn2n04n)\begin{pmatrix} 4^n & n 2^n \\ 0 & 4^n \end{pmatrix}(4n0n2n4n)
(2nn2n02n)\begin{pmatrix} 2^n & n 2^n \\ 0 & 2^n \end{pmatrix}(2n0n2n2n)