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Determinantshard
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Let AAA be a 3×33 \times 33×3 matrix with eigenvalues λ1,λ2,λ3\lambda_1, \lambda_2, \lambda_3λ1​,λ2​,λ3​. If det⁡(A)=6\det(A) = 6det(A)=6 and tr(A)=6\text{tr}(A) = 6tr(A)=6, find the value of the determinant of the matrix B=A2−6A+6IB = A^2 - 6A + 6IB=A2−6A+6I.