Let AAA be a 3×33 \times 33×3 matrix. If adj(adj(A))=kA\text{adj}(\text{adj}(A)) = kAadj(adj(A))=kA, find kkk.
det(A)\det(A)det(A)
det(A)2\det(A)^2det(A)2
det(A)n−2\det(A)^{n-2}det(A)n−2
1