Let A,B,CA, B, CA,B,C be sets. What is the dual of the distributive law A∩(B∪C)=(A∩B)∪(A∩C)A \cap (B \cup C) = (A \cap B) \cup (A \cap C)A∩(B∪C)=(A∩B)∪(A∩C)?
A∪(B∩C)=(A∪B)∩(A∪C)A \cup (B \cap C) = (A \cup B) \cap (A \cup C)A∪(B∩C)=(A∪B)∩(A∪C)
A∩(B∩C)=(A∩B)∩(A∩C)A \cap (B \cap C) = (A \cap B) \cap (A \cap C)A∩(B∩C)=(A∩B)∩(A∩C)
A∪(B∪C)=(A∪B)∪(A∪C)A \cup (B \cup C) = (A \cup B) \cup (A \cup C)A∪(B∪C)=(A∪B)∪(A∪C)
(A∩B)′=A′∪B′(A \cap B)' = A' \cup B'(A∩B)′=A′∪B′