Let AAA and BBB be events such that P(A)=0.6P(A) = 0.6P(A)=0.6, P(B)=0.4P(B) = 0.4P(B)=0.4, and P(A∣B)=0.25P(A | B) = 0.25P(A∣B)=0.25. Calculate the probability P(Ac∣Bc)P(A^c | B^c)P(Ac∣Bc).
0.33
0.5
0.66
0.75