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Recurrence Relations
easy
0:00.0
Is
a
n
=
2
n
a_n = 2^n
a
n
=
2
n
a solution to
a
n
=
2
a
n
−
1
a_n = 2a_{n-1}
a
n
=
2
a
n
−
1
?
A
Yes
B
No
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