In triangle ABCABCABC, use the Law of Cosines to find the angle CCC when a=10a = 10a=10, b=12b = 12b=12, and c=8c = 8c=8.
arccos(2140)\arccos(\frac{21}{40})arccos(4021)
arccos(3760)\arccos(\frac{37}{60})arccos(6037)
arccos(1115)\arccos(\frac{11}{15})arccos(1511)
arccos(4780)\arccos(\frac{47}{80})arccos(8047)