In △ABC\triangle ABC△ABC, ∠A=45∘,∠B=60∘\angle A = 45^\circ, \angle B = 60^\circ∠A=45∘,∠B=60∘, and a=10a=10a=10. Find side bbb.
565\sqrt{6}56
10310\sqrt{3}103
525\sqrt{2}52
10610\sqrt{6}106