In a triangle ABCABCABC, the orthocenter HHH satisfies AH=4,BH=3AH = 4, BH = 3AH=4,BH=3. If ∠ACB=60∘\angle ACB = 60^\circ∠ACB=60∘, find ABABAB.
5
\sqrt{13}
\sqrt{37}
7